Question

A 1,000 pound boat sits on a ramp inclined at 22°.
How much force is pulling down the ramp, and how much force is pressing on a line perpendicular to the ramp?

Answer 1

That question was already answered by some of our OS team: http://openstudy.com/study#/updates/51df4231e4b076f7da41762c

Answer 2

I looked at this but I don't understand how they came up with x = 1000cos(22)
The way I see it, it should be x = 1000/cos(22)

Answer 3

But I know I'm wrong

Answer 4

Let me get someone who is an Honorary Professor of Mathematics: @ganeshie8

Answer 5

I'm supposed to be using vectors, but how do I know which vector is u and which one is v?

A 1,000 pound boat sits on a ramp inclined at 22 deg.
How much force is pulling down the ramp, and how much force is pressing on a line pependicular to the ramp?

cos22 = vector v over 1000 -> magnitude of v = 1000(cos22) = 1000(.9272) = 927.2 pounds

sin22 = vector u over 1000 -> magnitude of u = 1000(sin22) = 1000(.3746) = 374.6 pounds

Thus, there is a force of 927.2 pounds acting against the ramp and a force of 374.6 pounds pulling down the ramp.

Answer 6

That's the answer, but I don't know how to get there

Answer 7

There is only gravity acting vertically downward :

Answer 8

Normal force is perpendicular to the ramp, right? I need to find that

Answer 9

Yes.