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Mathematics 16 Online
OpenStudy (sparklestaraa):

The graph of the following system of equations is

OpenStudy (sparklestaraa):

OpenStudy (sparklestaraa):

@TheSmartOne

HanAkoSolo (jamierox4ev3r):

first, you want to convert this to y=mx+b form. can you do this? @Sparklestaraa

OpenStudy (anonymous):

you can see that the second equation is three times the first equation. That means the first and the second equations are the same, so they are...?

HanAkoSolo (jamierox4ev3r):

to convert to y=mx+b, you have to solve for y Here's an example: 2x+y=6 -2x -2x -------- y=-2x+6 ^ does that make sense? now try the other equation @Sparklestaraa

OpenStudy (campbell_st):

myltiply every term in the 1st line by 3, what do you get..?

HanAkoSolo (jamierox4ev3r):

waiting for a response from the asker...

OpenStudy (sparklestaraa):

Ok

OpenStudy (hysusonic):

@Jamierox4ev3r i agree with @M4thM1nd because if you convert the lines to y=mx+b form, she'll just be doing extra work

OpenStudy (sparklestaraa):

6x + 3y = 18 3y=18+6x?

HanAkoSolo (jamierox4ev3r):

ah true i didn't even see that xDD but converting the equations makes it that much easier to see

HanAkoSolo (jamierox4ev3r):

@Sparklestaraa then divide everything by 3 3y=-6x+18 /3 /3 /3 --------- y=

OpenStudy (campbell_st):

here is my suggestion take the 1st line 3x + y = 6 and multiply every term by 3 \[3 \times 2x + 3 \times y = 3 \times 6\] what do you notice... that's all the calculation you need for the question

OpenStudy (hysusonic):

@campbell_st or divide the second equation by 3 which would make it easier for everyone to see

OpenStudy (hysusonic):

\[\frac{ 6x+3y=18 }{ 3 }\]

OpenStudy (campbell_st):

lol... funny thing is... people find multiplication easier than division... but its whatever @Sparklestaraa finds easier... I just posted my comment as it appeared that the methods suggested contained unnecessary steps

OpenStudy (hysusonic):

XD really @campbell_st ? i never knew that

OpenStudy (campbell_st):

so please choose whatever method you feels suits you.... the key to the question is looking 1st then thinking what you can do. it all comes with experience.

OpenStudy (sparklestaraa):

I don't know which is better i really don't still understand it

OpenStudy (campbell_st):

an alternate method is to graph both lines and study them that way.

OpenStudy (sparklestaraa):

oh no the graph is confusing in itself so idk whichever method is easier

OpenStudy (campbell_st):

every method posted will get you to a solution... so it depends on what skills you have and what you feel comfortable with.

OpenStudy (sparklestaraa):

idk maybe the multiplication but I'm lacking skills xD @campbell_st

OpenStudy (sparklestaraa):

@SyedMohammed98 :D SHUKRAN :D

syed98 (syedmohammed98):

|dw:1424633092263:dw|

OpenStudy (sparklestaraa):

They are parallel correct

syed98 (syedmohammed98):

yupp

OpenStudy (sparklestaraa):

@ThatOneGuy00

OpenStudy (campbell_st):

these lines aren't parallel multiply every term in the 1st line by 3 \[3 \times 2x + 3 \times y = 3 \times 6~~~~so~you~get~~~~6x + 3y = 18\] the 2nd line is 6x + 3y = 18 so you have the same line... or overlapping... the 1st line sits exactly on top of the 2nd line...

syed98 (syedmohammed98):

oops...sorry

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