Question

In simplified exponential notation, the expression x ³ • x -4 • x = _____

Answer 1

please we have
\[{x^3} \cdot x = {x^4}\]

Answer 2

yes

Answer 3

so I can rewrite your expression as follows:
\[{x^4} - 4x\]

Answer 4

x3.x-4.x=

Answer 5

so is 0?

Answer 6

or 1/x ?

Answer 7

no, please it is:
\[{x^3} \cdot x - 4 \cdot x = {x^4} - 4x\]

Answer 8

do not understand i only have 3 choices 1/x 0 1

Answer 9

?

Answer 10

is your original expression this?
\[\left( {{x^3} \cdot x} \right) - \left( {4 \cdot x} \right)\]

Answer 11

1/x?

Answer 12

please I aks help to another tutor @Abhisar

Answer 13

ty

Answer 14

@Nnesha

Answer 15

x3.x-4.x=

Answer 16

\(\tt x^{-4}~can~be~written~as~\frac{1}{x^4}\)

Answer 17

IS the initial problem, \(\large\color{slate}{ x^3\cdot x^{-4}\cdot x }\) ?

Answer 18

\(\large\color{slate}{ x^3\cdot x^{-4}\cdot x =x^{3-4+1}=x^{?} }\)

Answer 19

yes

Answer 20

what is the exponent here?

Answer 21

what is your expoentn can you tell me?

Answer 22

0

Answer 23

and the prove for \(\large\color{slate}{ x^0 }\)
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~

\(\large\color{slate}{ \displaystyle \color{red}{x^{0}}~~\Rightarrow ~~x^{a-a}~~\Rightarrow ~~\frac{x^a}{x^a}~~\Rightarrow ~~\color{red}{1} }\)

Answer 24

so what is your final answer ?

Answer 25

1/x

Answer 26

wait, you said the exponent is 0,

\(\large\color{slate}{ x^3\cdot x^{-4} \cdot x~~~\Longrightarrow~~~ x^3\cdot x^{-4} \cdot x^1~~~\Longrightarrow~~~ x^{3 +(-4)+1}~~~\Longrightarrow~~~ x^0. }\)

Answer 27

And as I showed \(\large\color{slate}{ x^0 }\) is equivalent to what number ?

Answer 28

This is so confusing :(

Answer 29

\[2^0 = 1\]
\[4^0 =1\]
\[b^0 = 1\]
when any number or variable have 0 exponent answer always going to be just 1

Answer 30

you said that x^0 right ???
that's what you got right ?? @Dyalis_love

Answer 31

are you there ???