Question

A neutron star has a density of about 5.9 10 17 kg/m3.

What would be the approximate mass of a 1-centimeter cube (a cube 1 cm on all sides)?

Answer 1

5.9 1014 kg (1300 trillion pounds)
5.9 108 kg (1.3 billion pounds)
5.9 1017 kg (1.3 quadrillion pounds)
5.9 1011 kg (1.3 trillion pounds)

those are the options

Answer 2

me1000

Answer 3

me10000

Answer 4

Ok so the density is 5.9* 10^17 kg/m^3. So what that means is 5.9 * 10^17 kg per m^3

Answer 5

pls tell me you got it

Answer 6

So if you change the bottom to cm^3 you will get the mass per cm^3

Answer 7

so its the third answer?

Answer 8

No because the is the density per m^3 you want the density per cm^3. So you have to convert the bottom to cm^3. Do you know how to do that?

Answer 9

no

Answer 10

So in every m there are 100 cm (10^2 cm) So for every m^3 there are 1,000,000 cm^3 (10^6). So if you want to get the bottom to turn into cm^3 you must divide by 10^6. this way the m^3's cancel out and cm^3 moves to the bottom

Answer 11

so the answer is ?

Answer 12

What do you think?

Answer 13

the second one?

Answer 14

plug in 5.9* 10^17 / 10^6 into a calculator

Answer 15

i got 5.9e11

Answer 16

Which is the same as which answer?

Answer 17

the last one

Answer 18

thanks

Answer 19

no problem

Answer 20

can u still help me

Answer 21

with other questions