dy/dt of y=(ln(2t))/(5t)
y = a/b ; y' = (ba' - ab')/b^2
Yes I know it's the quotient rule but somewhere I am messing up... can't find my error
I get ((ln(2t)*5)-((1/2t)*2)(5t))/(5t^2) which is incorrect, sorry for all the parenthesis it's how I have to enter it on on the website haha
trying denominator*(derivative of numerator) - (numerator)*derivative of denominator
Yeah I understand that I'm just messing up somewhere I suppose... Can't find it though it's really frustrating!
deriv of ln(2t) = (1/2t)*2 right?
yes
Idk then.. my answer looks 100% right to me but it isn't! :(
i got (1-ln2t)/5t^2. is that right?
Nope sadly
\(\large\color{black}{ \displaystyle y=\frac{\ln(2t) }{5t} }\) \(\large\color{black}{ \displaystyle \frac{dy}{dt}=\frac{\frac{1}{t}(5t)+5\ln(2t) }{(5t)^2} }\) \(\large\color{black}{ \displaystyle \frac{dy}{dt}=\frac{5+5\ln(2t) }{25t^2} }\) \(\large\color{black}{ \displaystyle \frac{dy}{dt}=\frac{1+\ln(2t) }{5t^2} }\)
firstly the way you started is incorrect you must abide the order when you do the quotien rule unlike the product rule where you can start with any
I differnetiated the top function, except I wrote the + instead of -
\(\large\color{black}{ \displaystyle \frac{dy}{dt}=\frac{1-\ln(2t) }{5t^2} }\)
thats what i got
F(x)/G(x) = { F`(x) G(x) - F(x)G`(x) } / G^2(x)
@ineptAtMath yes your answer is correct
Okay you were right ineptatMath. I needed to add a parenthesis
and why is derivative of any ln(Ct) with respect to t is 1/t \(\large\color{black}{ \displaystyle (~\ln(Cx)~)'=\frac{1}{Cx}\times C }\) or \(\large\color{black}{ \displaystyle (~\ln(Cx)~)'=(~\ln(x)+\ln(C)~)'=\frac{1}{x}+0=\frac{1}{x} }\)
So in ln(Cx) (had a typo in the beginning) is just a vertical shift of ln(x) , C units up
(1-ln2t) needed to be (1-ln(2t)) lol
Thanks for the explanation and help guys! Going to go over what you've sent so I can see what I did wrong
;)
Oh sorry about that!
abt what /
?
the lack of parenthesis in what i wrote was confusing
oh, if you write a space, it is most fine, but yes, don't leave your parenthesis out, becuase not everyone will see the typo behind it.
I hand-written my essay once, and my "second" looked like "secont" (in 8th grade) And that brought my paper from 98 to 93.
duly noted! ^^ And omg..... just one misspelled word dropped you down 5%? Harsh
no, for that mistake in 8th grade, it is just like not knowing what integral is in calculus 2.
it is not as low level mistake to assume a typo, but not as high to go over...
anyway.... \(\Huge\bf\rlap{\color{red}{G\ o\!}}{\color{blue}{\; {G\ o\ }}}\)\(\Huge\bf\rlap{\color{red}{o\ d\ }}{\color{blue}{\; {o\ d\ }}}\) \(\Huge\bf\rlap{\color{red}{L\ u\!}}{\color{blue}{\; {L\ u\ }}}\)\(\Huge\bf\rlap{\color{red}{c\ k\ }}{\color{blue}{\; {c\ k\ }}}\) \(\Huge\bf\rlap{\color{red}{~!}}{\color{blue}{\; ~{!}}}\)
Haha okay! Good luck to you too :)
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