Write the sum using summation notation, assuming the suggested pattern continues. -9 - 3 + 3 + 9 + ... + 81
@e.mccormick
darn, clicked the wrong thing...
closed means you succeeded
lol
oh so no
so hmm we need to find a pattern
I meant to click delete, but instead clicked close because it moved right as I clicked lol
so it really goes like this...-9,-3,3,9,...,81
it looks like this is an arithmetic sequence
do you see the common difference?
-3-(-9)=? 3-(-3)=? 9-3=? all of these are equal to what?
adding 6
yep do first I'm going to play with this sequence then I will go back to the series you mentioned
\[a_n=a_1+d(n-1)\] d is the common difference and a_1 is the first term in the sequence
you already identified d
as 6
now a_1 is ?
-9 so \(a_n\)=-9+6(n-1)
right we need to figure out for what number n is the last term 81
\[81=-9+6(n-1)\] a_n is 81 but what is n well solve this for n to find out :)
81 = -9 + 6n - 6 81 = -15 + 6n 96 = 6n 16 = n
\[\text{ your answer is going \to be \in this form } \sum_{n=1}^{16}a_n\] last step just replace a_n with what you found above
The -9 + 6n?
-9+6(n-1)
hmmm... I guess I will go with the option closest to that... which isn't really any of them o.O
\[\sum_{n=1}^{16}a_n=\sum_{n=1}^{16}(-9+6(n-1))\] you could combine like terms and there are also other ways to write the summation but you are done you did what it said which was write as a summutation
Well let me ask you a question
do they start it at n=0 ...
or some other number
I don't know what they start it at, that was all the information given :/
oh i thought they gave you choices
it sounded like you were saying oyu have to select an option
so all the choices start off with n=0
do you see that
ours starts off at n=1
we can manipulate that
\[\sum_{n=1}^{16}a_n=\sum_{n=1}^{16}(-9+6(n-1)) \\ \\ \sum_{n=1}^{n=16}(-9+6(n-1)) \\ \sum_{n-1=0}^{n-1=15}(-9+6(n-1))\]
now replace n-1 wherever you see n-1 with new n
\[\sum_{n=0}^{n=15}(-9+6(n))\]
that makes more sense :) thanks for coming to help even though I accidentally closed it haha
do you see how i manipulated like we had from n=1 to n=16 I subtracted 1 on both sides for these equations n=1 n-1=1-1 n-1=0 and n=16 n-1=16-1 n-1=15 and our expression was already in terms of (n-1)
yes
cool stuff
also the bottom two make no since because we do not have an infinite series :) and the second one also doesn't make sense because none of the beginning terms in your sequence are multiples of -54 so I think you could have done less work here and just used process of elimination a long with common sense but it is also nice to see how to set it up :)
I figured it was the first one, but I didn't want to just pick an option, I wanted to know how to do it
And I totally think that is cool :)
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