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Mathematics 22 Online
OpenStudy (anonymous):

Find each of these values. a) (19^2 mod 41) mod 9 b) (32^3 mod 13)^2 mod 11 c) (7^3 mod 23)^2 mod 31 d) (21^2 mod 15)^3 mod 22

ganeshie8 (ganeshie8):

show what have you tried and where are you stuck..

OpenStudy (anonymous):

i dont understand it at all

OpenStudy (anonymous):

@ganeshie8 im sorry letter d is what im really focused on right now i don't understand a single thing

ganeshie8 (ganeshie8):

maybe lets look at letter a first

ganeshie8 (ganeshie8):

19^2 mod 41 gives you the remainder when 19^2 is divided by 41

ganeshie8 (ganeshie8):

whats the remainder when you divide 19^2 by 41 ?

OpenStudy (anonymous):

8.8?

ganeshie8 (ganeshie8):

remember we only work with integers

OpenStudy (anonymous):

so is it 9

ganeshie8 (ganeshie8):

19^2 = 361 divide that by 41 : |dw:1424680827076:dw|

ganeshie8 (ganeshie8):

how many times 41 goes in 361 ?

OpenStudy (anonymous):

8

OpenStudy (anonymous):

with 33 remainder

ganeshie8 (ganeshie8):

yes! 8*41 = 328 : |dw:1424680911572:dw|

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