Question

Design an amplifier to give a 60 dB amplification to an input signal of frequency 100 kHz. Use an Op Amp having GBW = 10^7 Hz & SR = 10^7 V/sec. Determine the maximum amplitude of the input signal.

Answer 1

60 dB corresponds to a voltage gain of 20, with a GBW of 100 MHz means the amplifier will have a BW of 5 MHz, as for the Slew Rate, SR, that will depend on the input signal shape, sinusoidal or square wave. I would be interested in you SR analysis.

Answer 2

Error
dB = 20 Log[voltage gain]
therefore
60 = 20 Log{voltage gain}
voltage gain = 10^3
GBW = 100 MHz therefore the 3 dB BW is
100 MHz/(1000) = 100 KHZ
Sorry, I was to quick in my previous response