Question

What is the radius of a circle represented by the given equation?
x2 + y2 – 4x – 6y + 12 = 0?

Answer 1

@aum

Answer 2

Huey Freeman?

Answer 3

That Be me

Answer 4

Cool :D

Answer 5

Its either 5 or 12

Answer 6

x^2 + y^2 – 4x – 6y + 12 = 0
Group the x-terms together and the y-terms together:
(x^2 - 4x) + (y^2 - 6y) + 12 = 0
Complete the square of x^2 - 4x
Complete the square of y^2 - 6y

What do you get?

Answer 7

12

Answer 8

You need to complete the square first.

Answer 9

Idk

Answer 10

@aum

Answer 11

Looks like you just want answers and I am sorry I can't do that.
You should learn how to complete squares.

Answer 12

I think I know what your talking about but I dont want to do anything wrong

Answer 13

Im unsure

Answer 14

(x-2)^2 +(y-3)^2 =12+ (-2)^2 +(-3)^2

Answer 15

The 12 on the RHS should be -12.

Answer 16

(x-2)^2 +(y-3)^2=

Answer 17

(x-2)^2 +(y-3)^2 =-12+ (-2)^2 +(-3)^2
(x-2)^2 +(y-3)^2 =-12+ 4 + 9 = -12 + 13 = 1
(x-2)^2 +(y-3)^2 =1 = (1)^2
Compare it to: (x-h)^2 + (y-k)^2 = r^2
where (h, k) is the center of the circle and 'r' is the radius.
They just want 'r' in this problem. r = ?

Answer 18

1

Answer 19

(x-2)^2 +(y-3)^2 = (1)^2
(x-h)^2 + (y-k)^2 = r^2

r = ?

Answer 20

r=1

Answer 21

?

Answer 22

correct. The radius is 1.

Answer 23

ok thx

Answer 24

yw.