Ask
your own question, for FREE!
Mathematics
12 Online
OpenStudy (anonymous):
Is the function f(x) = 3x2 + 1 odd, even, or neither?
I'm not sure what this question is looking for. I made a table and got odd and even #s for y.
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (misty1212):
HI!!
OpenStudy (misty1212):
polynomial it is easy to tell all the exponents have to be odd
OpenStudy (misty1212):
that is to be odd
to be even, all the exponents have to be even
OpenStudy (diamondboy):
if f(-x) is = -f(x) den its odd
OpenStudy (diamondboy):
dats another way
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (misty1212):
in your case you have \(3x^2\) an even power, and also \(1\) which has degree 0
both 2 and 0 are even, so it is even
OpenStudy (misty1212):
so for example you will see that
\[f(2)=13\] and also
\[f(-2)=13\] that is a good indication that it is even
OpenStudy (misty1212):
the proof is that
\[f(x)=f(-x)\]
OpenStudy (anonymous):
I agree with @misty1212
OpenStudy (anonymous):
great that makes sense thanks every one :)
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (misty1212):
@bingtamekia thanks dear!
OpenStudy (diamondboy):
if f(-x) = F(x) den its even
OpenStudy (diamondboy):
so dey are both right
OpenStudy (diamondboy):
I meant @misty1212 and @bingtamekia
OpenStudy (misty1212):
\[\color\magenta \heartsuit\]
Can't find your answer?
Make a FREE account and ask your own questions, OR help others and earn volunteer hours!
Join our real-time social learning platform and learn together with your friends!