Is the function f(x) = 3x2 + 1 odd, even, or neither? I'm not sure what this question is looking for. I made a table and got odd and even #s for y.
HI!!
polynomial it is easy to tell all the exponents have to be odd
that is to be odd to be even, all the exponents have to be even
if f(-x) is = -f(x) den its odd
dats another way
in your case you have \(3x^2\) an even power, and also \(1\) which has degree 0 both 2 and 0 are even, so it is even
so for example you will see that \[f(2)=13\] and also \[f(-2)=13\] that is a good indication that it is even
the proof is that \[f(x)=f(-x)\]
I agree with @misty1212
great that makes sense thanks every one :)
@bingtamekia thanks dear!
if f(-x) = F(x) den its even
so dey are both right
I meant @misty1212 and @bingtamekia
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