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Mathematics 16 Online
OpenStudy (anonymous):

Is the function f(x) = 3x2 + 1 odd, even, or neither? I'm not sure what this question is looking for. I made a table and got odd and even #s for y.

OpenStudy (misty1212):

HI!!

OpenStudy (misty1212):

polynomial it is easy to tell all the exponents have to be odd

OpenStudy (misty1212):

that is to be odd to be even, all the exponents have to be even

OpenStudy (diamondboy):

if f(-x) is = -f(x) den its odd

OpenStudy (diamondboy):

dats another way

OpenStudy (misty1212):

in your case you have \(3x^2\) an even power, and also \(1\) which has degree 0 both 2 and 0 are even, so it is even

OpenStudy (misty1212):

so for example you will see that \[f(2)=13\] and also \[f(-2)=13\] that is a good indication that it is even

OpenStudy (misty1212):

the proof is that \[f(x)=f(-x)\]

OpenStudy (anonymous):

I agree with @misty1212

OpenStudy (anonymous):

great that makes sense thanks every one :)

OpenStudy (misty1212):

@bingtamekia thanks dear!

OpenStudy (diamondboy):

if f(-x) = F(x) den its even

OpenStudy (diamondboy):

so dey are both right

OpenStudy (diamondboy):

I meant @misty1212 and @bingtamekia

OpenStudy (misty1212):

\[\color\magenta \heartsuit\]

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