Determine whether the series is divergent or convergent
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OpenStudy (johnnydicamillo):
\[\sum_{n =1 }^{\infty} \frac{ n }{ 1 + \sqrt{n} }\]
OpenStudy (johnnydicamillo):
actually this is a sequence of partial sums
OpenStudy (johnnydicamillo):
so I take the limit as n goes to infinity right
OpenStudy (misty1212):
hi!!
OpenStudy (misty1212):
eyeball it
the degree of the numerator is larger than the degree of the denominator, so the terms don't even to go zero
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OpenStudy (johnnydicamillo):
so divergent because n = infinity
OpenStudy (johnnydicamillo):
and not 0
OpenStudy (misty1212):
\[\lim_{n\to\infty}\frac{n}{1+\sqrt{n}}=\infty\]
the terms get larger and larger
so since the terms do not go to zero, there is no way the sum converges
you are adding larger and larger numbes
OpenStudy (johnnydicamillo):
awesome thanks!
OpenStudy (misty1212):
\[\color\magenta\heartsuit\]
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OpenStudy (misty1212):
btw it is not enough for the terms to go to zero
they have to go to zero fast enough
but since these terms do not even go to zero, no other consideration need apply
OpenStudy (kainui):
I totally agree with @misty1212 on doing the eyeball test. Also, you can do L'Hopital's rule to evaluate the limit.