Mathematics
8 Online
OpenStudy (anonymous):
(4x^2+4x-2)+ (-9x^2+ 7)
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OpenStudy (anonymous):
ok so the first step is to add like terms
OpenStudy (kc_kennylau):
Well, you can take away the parentheses first
OpenStudy (anonymous):
how would I do that @kc_kennylau
OpenStudy (kc_kennylau):
Just try to write it without the parentheses
OpenStudy (kc_kennylau):
And be careful that (a-b)-(c-d) = a-b-c+d (this case doesn't apply here)
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OpenStudy (anonymous):
the problem states that it is addition
OpenStudy (kc_kennylau):
The first step would be like this:
(4x^2+4x-2)+ (-9x^2+ 7)
=4x^2+4x-2-9x^2+7
OpenStudy (kc_kennylau):
Do you understand this
OpenStudy (anonymous):
combining like terms
OpenStudy (kc_kennylau):
this step is not combining like terms though, but it is the next step
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OpenStudy (anonymous):
so I take-1 from the second parentheses?
OpenStudy (kc_kennylau):
Nah
OpenStudy (kc_kennylau):
Or like this:
(4x^2+4x-2)+ (-9x^2+ 7)
=4x^2+4x-2+ -9x^2+ 7
=4x^2+4x-2-9x^2+7
OpenStudy (anonymous):
confusing me?
OpenStudy (kc_kennylau):
Well, I just took away the parentheses
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OpenStudy (anonymous):
k...next step
OpenStudy (kc_kennylau):
Well, we would regroup the terms:
4x^2+4x-2-9x^2+7
=4x^2-9x^2+4x-2+7
OpenStudy (kc_kennylau):
do u understand this
OpenStudy (anonymous):
you distributed -1in the second parentheses
OpenStudy (kc_kennylau):
Well, I don't think I did, since the operation in front of the second parentheses is plus instead of minus
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OpenStudy (anonymous):
it looks like you grouped everything (like terms)together...but idk
OpenStudy (kc_kennylau):
well, I just took away the parentheses
OpenStudy (kc_kennylau):
Let's use numbers to understand that: (3+4)+(-9+7) = 3+4-9+7
OpenStudy (anonymous):
ok...you took away the parentheses
OpenStudy (kc_kennylau):
So this is the next step:
4x^2+4x-2-9x^2+7
=4x^2-9x^2+4x-2+7
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OpenStudy (kc_kennylau):
Sorry I have to go now