Question

-( )y^2 − [-5y − y(-7y − 9)] − [-y (15y + 4)] = 0 How do I find the missing term?

Answer 1

Oh gosh, I'm sorry, i have no idea =)
@pooja195 @phi

Answer 2

you will want to combine like terms.... simplify that mess until you can see what is what.

Answer 3

for example, tackle the last term:
[-y (15y + 4)]

distribute the -y (that means multiply -y times each term inside the parens)
can you do that ?

Answer 4

-15y^2-4y right?

Answer 5

yes

we have to be careful. so far we have
-( )y^2 − [-5y − y(-7y − 9)] − (-15y^2-4y) = 0
I would "distribute the -1"
in
− (-15y^2-4y)

which is the same as
-1* (-15y^2-4y)

what do we get ?

Answer 6

refresh your browser if that did not display correctly

Answer 7

15y^2+4y ?

Answer 8

ok. now we have
-( )y^2 − [-5y − y(-7y − 9)] +15y^2 + 4y = 0
now tackle the middle stuff:
− [-5y − y(-7y − 9)]

Answer 9

is it (5y-y)(-7y-9)?

Answer 10

if we distribute the -1 out front:
−1* [-5y − y(-7y − 9)] = -1* -5y + -1*-y *(-7y-9)

Answer 11

no it's not (5y-y)(-7y-9)
you should get
5y +y(-7y-9)
and now distribute the y

Answer 12

5y-7y^2-9y ?

Answer 13

yes.
now it's
-() y^2 + 5y-7y^2-9y+15y^2 + 4y = 0

now look for "like terms"
which means y to the same power
ignoring the first term (for the moment)
we have -7y^2 + 15y^2
can you simplify that ?

Answer 14

8y^2

Answer 15

and we have 5y -9y +4y which adds up to 0y or just 0

Answer 16

- () y^2 +8y^2 = 0

Answer 17

9y^2=0

Answer 18

I think the () means fill in a number so you get 0 out of the equation
in other words, replace () with a number.

Answer 19

I would pick 8

Answer 20

-9y^2 ?

Answer 21

because
-8y^2 + 8y^2 = 0

Answer 22

the idea is we want it to be true no matter what value y is

Answer 23

o ok . JUst 8 or -8y^2

Answer 24

they ask
-( )y^2 − [-5y − y(-7y − 9)] − [-y (15y + 4)] = 0 How do I find the missing term?

It looks like if we put in 8 where the () is, then we will get 0 out (after simplifying)
so just 8

Answer 25

Much obligied @phi