Question

Could someone please explain how to work this out step by step? It is easy, but I am getting confused. THANKS! ~Bree

x^2 - 10xy + 24y^2

Answer 1

so what is the question, baby?

Answer 2

it is posted above, but here it is :\[x^2 -10xy+24y^2\]

Answer 3

what do you have to do with that function?

Answer 4

graph? factor? solve for x?

Answer 5

I have to factor it

Answer 6

ok

Answer 7

I forgot how to do it with two variables lol

Answer 8

Simplifying
x2 + -10xy + 24y2

Reorder the terms:
-10xy + x2 + 24y2

Factor a trinomial.
(x + -6y)(x + -4y)

Final result:
(x + -6y)(x + -4y)

Answer 9

how do you factor it though? im not used ot have multiple letters...

Answer 10

let me work it out! one sec

Answer 11

do you know how to factor u^2-10u+24?

Answer 12

yes

Answer 13

what do you get when you factor it

Answer 14

(u-4)(u-6) ?

Answer 15

x^2-10xy+24y^2 is the same way
you will have (x-4y)(x-6y)

Answer 16

x^2+Bxy+Cy^2
if factorable will look something like this:
(x+ny)(x+my)

Answer 17

ok, i think I see what you are talking about. so i just have to insert the "y" into both sets of parenthesis?

Answer 18

yeah next to that last number in each
so when you multiply the last times the last
you will get -4y(-6y)=24y^2 which is the last term in your expression

Answer 19

ohhhh, thanks! I am pretty sure i understand :)

Answer 20

and when you do first times the last from both
that is you do x(-6y)+(-4y)x=-6xy-4xy you get -10xy :)

Answer 21

i get it! thank you so much!! :D

Answer 22

which is your middle term in this case

Answer 23

the middle term would be -10xy right? i might have this wrong :/

Answer 24

yes the middle term is -10xy :)
other examples:

\[x^2+5xy+6y^2 =(x+2y)(x+3y)\]
\[x^2-4xy+3y^2=(x-3y)(x-1y) \text{ or } (x-3y)(x-y)\]

Answer 25

thank you :) im taking a screen shot for future reference lol :)