@TheSmartOne The first five terms of a sequence are shown below: 6, 9, 12, 15, 18 If the nth term of this sequence is represented by f(n), which of the following functions best represents this sequence? f(n) = 6n - 3; n ≥ 1 f(n) = 6n + 3; n ≥ 1 f(n) = 3n + 3; n ≥ 1 f(n) = 3n - 3; n ≥ 1
b?
Nope
What's the difference between each term?
@Supermariofan153 Please no direct answers. Its against the CoC http://openstudy.com/code-of-conduct
each is 3 more than each other
ok
@DDCamp
The difference between each term will be what you multiply n by. (So if n goes up by one, the term goes up by 3). Does that make sense?
yes @DDCamp
Since 6 is the first number then when n=1 then f(n)=6
So when n=1, f(n) = 6 n=2, f(n)= 9 and so on
So basically plug in those numbers and you got it :)
ok so basically c @TheSmartOne
Yup :D
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thank you @TheSmartOne
Np :)
A sequence has its first term equal to 3, and each term of the sequence is obtained by adding 5 to the previous term. If f(n) represents the nth term of the sequence, which of the following recursive functions best defines this sequence? f(1) = 3 and f(n) = f(n - 1) + 5; n > 1 f(1) = 5 and f(n) = f(n - 1) + 3; n > 1 f(1) = 3 and f(n) = f(n - 1) + 5n; n > 1 f(1) = 5 and f(n) = f(n - 1) + 3n; n > 1
@TheSmartOne c o. d
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