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Mathematics 19 Online
OpenStudy (quickstudent):

Are these correct? simplifying rational expressions.

OpenStudy (quickstudent):

1.) 100/x + 100/(x + 1) 100/x * (x + 1)/(x + 1) = (100x + 100)/(x^2 + x) 100/(x + 1) * x/x = 100x/(x^2 + x) (100x + 100)/(x^2 + x) + 100x/(x^2 + x) = (200x^2 + 100)/(x^2 + x)

OpenStudy (quickstudent):

2.) 15/(x + 8) + 10/x 15/(x + 8) * x/x = (15x + 120)/(x^2 + 8x) 10/x * (x + 8)/(x + 8) = (10x + 80)/(x^2 + 8x) (15x + 120)/(x^2 + 8x) + (10x + 80)/(x^2 + 8x) = (25x + 200)/(x^2 + 8x)

OpenStudy (idealist10):

The first one is wrong. Let me show you my work.

OpenStudy (idealist10):

\[\frac{ 100 }{ x }+\frac{ 100 }{ x+1 }=\frac{ 100x+100+100x }{ x(x+1) }=\frac{ 200x+100 }{ x^2+x }\]

OpenStudy (idealist10):

The second one is also wrong. Let me show you my work.

OpenStudy (idealist10):

\[\frac{ 15 }{ x+8 }+\frac{ 10 }{ x }=\frac{ 15x+10x+80 }{ x^2+8x }=\frac{ 25x+80 }{ x^2+8x }\]

OpenStudy (quickstudent):

Wait, how did you get x^2 + x out of that? I thought when adding fractions the denominator is supposed to stay the same?

OpenStudy (quickstudent):

@Idealist10

OpenStudy (idealist10):

Yes, it stays the same. But it looks nicer because x(x+1)=x^2+x, you get it?

OpenStudy (idealist10):

You just distribute x(x+1) to get x^2+x.

OpenStudy (quickstudent):

Oh, I see now. So my answer was correct, it just wasn't completely simplified.

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