PLEASE HELP WILL AWARD MEDAL!

The pressure exerted on a 243 mL sample of hydrogen gas at constant temperature is increased from 0.428 atm to 0.724 atm. What will the final volume of the sample be?

Question

PLEASE HELP WILL AWARD MEDAL! 


The pressure exerted on a 243 mL sample of hydrogen gas at constant temperature is increased from 0.428 atm to 0.724 atm. What will the final volume of the sample be?

noelgreco · Answer

PV=nRT  The right side of the formula is assumed constant, so
$$P _{1}V _{1}=P _{2}V _{2}$$

technodynamic · Answer

$$(243mL H_2)(0.428 atm) = (0.724 atm) (x)$$

technodynamic · Answer

$$104.0 atm mL H_2 = 0.724$$

technodynamic · Answer

$$143.6 mLH_2 = x$$

technodynamic · Answer

$$v_f = 144 mLH_2$$

anonymous · Answer

Can i just say.. youre too generous. Thank you @Technodynamic

technodynamic · Answer

You're welcome! :)

anonymous · Answer

If you dont mind this is my last initial question... I read it and does it or does it not want me to convert to Kelvin? 
A sample of air has a volume of 140 mL at 62 ºC. At what temperature (in ºC) would its volume be 50.0 mL at constant pressure?

Round to the nearest whole number. Don't forget to convert your temperatures. 
@Technodynamic

anonymous · Answer

I got 140/335K= .4179 divided by 50.0

anonymous · Answer

and got .008358

anonymous · Answer

But how should i submit the answer as? @Technodynamic

anonymous · Answer

@NoelGreco