PLEASE HELP ASAP. THANK YOU
Consider the following.
f(x) = 3x^3 + 6x^2, x = − 1/2
For the given function, find the point of tangency and slope of the tangent line at the indicated value of x.

Question

PLEASE HELP ASAP. THANK YOU 
Consider the following.
f(x) = 3x^3 + 6x^2,      x = − 1/2
For the given function, find the point of tangency and slope of the tangent line at the indicated value of x.

diamondboy · Answer

d slope of d tangent line= derivative of f(x)

diamondboy · Answer

den plug in d value of x given yo u into d derivative of f(x)

anonymous · Answer

Wait so I did the derivative and got 9x^2 + 12x...thats my slope of the tangent line?

jim_thompson5910 · Answer

now you plug x = -1/2 into 9x^2 + 12x to get your tangent slope

jim_thompson5910 · Answer

to find the point of tangency, you plug x = -1/2 into the function itself to get the y coordinate

diamondboy · Answer

^ correct @jim_thompson5910

anonymous · Answer

so I got 33/4...is that right for the tangent slope??

jim_thompson5910 · Answer

incorrect

anonymous · Answer

so I made a stupid error, and tried it again and got -3.75

diamondboy · Answer

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