if there is four polynomials and two of them have the same heist exponent which one is higher? really confusing
Are you talking about like same base and same exponent? OR, Same base different exponent? OR, Different base same exponent?
FAN AND MEDEL!!!
DIFF BASE SAME HIEST exponent
like this x + 2xyz 3x + y + z 2x3y + y2x - 3x + 4 9x3yz
the three s are the hiest powers
In multiplication, just add the powers irrespective of the base..
only the bottom two have a exponent its the three i have to put them in order from highest to least or what ever
Like : \(x + 2xyz\), here, Degree is \(3\)..
but how there is no third power
See: \(x^3, y^2, x^2 y, xy^2, xyz\) all have degree of \(3\) in my knowledge..
*\(y^3\)
I am saying that in multiplication, add all the powers of variables, whether they are same or different, that will make the Highest power..
ohh i see tvvm i under stand thank u thanku
In \(xyz\), \(x\) has 1, y has 1 and z has 1, so add all 1s as x,y,z are in multiplication..
thank u very very much
Good.. :)
\(\dagger\)
so how would they e in order ?
@eta
You try first..
Tell me what you think, I correct you wherever needed..
i think it is 3. x + 2xyz 4.3x + y + z 1 .2x3y + y2x - 3x + 4 2 .9x3yz
i put numbers there 1-4
@eta
Good.. Right..
but their is no answer that says that
answers are 2,3,4,1 4,2,1,3 3,2,1,4 or 4,2,3,1
i said 3,4,1,2
i mean 2 3 1 4 2 1 3 4 1 2 4 3 3 1 4 2
@eta
Which order you want them in?
Ascending or descending?
From Highest to least.. Okay, I am writing down all four, correct me if I am wrong somewhere. \[ x + 2xyz \\ 3x + y + z \\ 2x^3y + y^2x - 3x + 4 \\ 9x^3yz\]
See, for the last one, add powers, 3+1+1 = 5, so First will be this..
\[x + 2xyz \; \; \; (3)\\ 3x + y + z \; \; \; (4) \\ 2x^3y + y^2x - 3x + 4 \; \; \; (2) \\ 9x^3yz \; \; (1)\]
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