Question

physics question!

Answer 1

#5, the red question has part a and b which I am confused to how to solve it.

Answer 2

It is related to KE and PE.

Answer 3

conservation of energy. he has zero velocity at the top of the first peak, then drops 12.5m. that height (meaning gravitational potential energy relative to lowest point) is converted to kinetic energy. ie mg∆h -->> (1/2)mv^2. ∆h = 12.5m

solve that for the first part.

the second part is similar save that he loses kinetic energy due to rising 7.5m. but same idea.

Answer 4

How can you do it when you do not have the mass?

Answer 5

Can you please show your work to me with explanation? Thank you.

Answer 6

It is because when you equate a KE and PE equations, the masses are the same, hence is the same as cancelling them out.

Answer 7

indeed.
Potential Energy --->>> Kinetic Energy
mg∆h -->> (1/2)mv^2
therefore g∆h -->> (1/2)v^2