how many atoms of iron are in 74 grams of Fel3
I don't know what "l" is in your compound. Whatever it is, just get the amount of grams FE has (iron), get the amount of moles. And multiply the amount of moles with avogadro's number
Number 13
I is iodine Grams of Iron (III) triiodide*(molecular mass of Fe/Molecular Mass of Iron (III) triiodide) = Grams of Iron The formula above is called gravimetric factor, think of it as units canceling, the Iron (III) triiodide cancels out (since the units are divided) and you are left with with Just Fe. This formula works the same way going back if you multiply grams of Iron by (molecular mass of Iron (III) triiodide/molecular Fe) you would get grams of Iron (III) triiodide (FeI3). Convert grams of Iron to moles of Iron using the formula: Moles = Grams/Molecular Mass Convert Moles to atoms by using avagadros number (6.02214129*10^23 atoms/mol) *mol of Iron = Atoms of Iron
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