Quick help for a bonus
on the basis of the solubility rules, suggest on method by which you might seperate the ammonium ion (NH4+) from the barium ion (Ba2+). Assume these ions are already dissolved in solution along with a spectator ion like the chloride ion (Cl-). Hint , solids and liquids are easily separated by filtration.

Question

Quick help for a bonus 
on the basis of the solubility rules, suggest on method by which you might seperate the ammonium ion (NH4+) from the barium ion (Ba2+). Assume these ions are already dissolved in solution along with a spectator ion like the chloride ion (Cl-). Hint , solids and liquids are easily separated by filtration.

anonymous · Answer

I would say first step: separation.
Being left with NH4+ and Ba2+ ions, we simply gently heat the solution, where ammonia will come out as a pungent gas and you can approach a netral litmus paper that will go blue.
Finally you have Ba2+ in the solution and Nh3 in air.