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Differential Equations
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Hi everyone! Can someone help me factor r^3 + 3r^2 - 4 = 0 please? My book says it is obvious that by inspection one of the roots are r=1...not so obvious to me. Thanks! :o)
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\[1+3-4=0\] is more or less obvious
if \(r=1\) you add the coefficients that is always true
well if you plug in 1 for r you get 1^3 + 3*1^2 - 4 = 0
@satellite...why is it okay to do 1+3-4=0 i mean what about grouping or all the other methods of solving...please explain why it's okay to just look at the coefficients in that way
HI!! why does everyone start with "well" seem rather affected to me as does "you just..."
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1 to any power is 1
so for example if you have \[f(x)=4x^3+5x^2+2x-1\] then \[f(1)=4+5+2-1\]
|dw:1425305141752:dw|
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