Celeste made 6 cone-shaped ice blocks that each have radius of 2.8 in. and a height of 7 in. She used a cylindrical container with a radius of 9 in. to fill all of the cones. What is the height of the cylindrical container? Use 3.14 to approximate pi and round your answer to two decimal places. Show your work. Will give medal!!!!
@bohotness
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Can you help?
Someone help?! @Data_LG2
first you have to know the formula of a cone? do you know the formula?
Yep! V=1/3pi*r^2h
okay great :D so now you have to calculate the volume of one CONE using that formula
i'll tell you the next step after you done with that :)
Okay so I got 57.44106(repeating)7
why you multiply it by 7? shouldn't it be 6?
No the six is repeating and stops the 6s
* 7*
" 6 cone-shaped ice blocks "
so it means, after you find out the value of the volume of one cone, you have to multiply it by 6... this outcome will be the volume of the cylinder
okay so that's 344.6464
\(\sf \large \frac{1}{3} \pi r^2h= \frac{1}{3}(3.14)(2.8)^2(7)= 9.2022\) multiply it by 6 because you have 6 cones, that will be \(\sf 9.02 \times 6 = 55.21\) this will be equal to the volume of the cylinder (: do you know the formula?
Sorta
The answer is 6.13 isnt it
\(\sf V= \pi r^2h\\55.21= (3.14)(9)^2h\) solve for h \(\sf \large h=\frac{55.21}{(3.14)(9^2)}\)
oops i made a mistake somewhere
hmm give me a sec..
\(\color{blue}{\text{Originally Posted by}}\) @Data_LG2 \(\sf \large \frac{1}{3} \pi r^2h= \frac{1}{3}(3.14)(2.8)^2(7)= 9.2022\) multiply it by 6 because you have 6 cones, that will be \(\sf 9.02 \times 6 = 55.21\) this will be equal to the volume of the cylinder (: do you know the formula? \(\color{blue}{\text{End of Quote}}\) this should be \(\sf \large \frac{1}{3} \pi r^2h= \frac{1}{3}(3.14)(2.8)^2= 8.2058 \times 6=49.23\) \(\sf V= \pi r^2h\\49.23= (3.14)(9)^2h\) solve for h \(\sf \large h=\frac{49.23}{(3.14)(9^2)}=0.18\) hmm this is kind of strange....
@confluxepic sorry i tagged you, can you help me please? tso is not online
@TheSmartOne
This is confusing.
Everything looks correct. Hmm, @iambatman @Directrix @whpalmer4 Can uoi please check? Thanks :)
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