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Mathematics 19 Online
OpenStudy (anonymous):

gdg

OpenStudy (anonymous):

Is it -3(2-3x)e^x?

Miracrown (miracrown):

Very close, this is product rule

Miracrown (miracrown):

\[(2-3x)e^x\] \[(2-3x)^\prime e^x \space + (2-3x) \space (e^x)^\prime\] \[-3e^x \space + \space (2-3x)e^x\]

OpenStudy (anonymous):

Is my answer still acceptable? Or do i need to rearrange this?

Miracrown (miracrown):

(fg)'=f'g+fg' first the derivative one times the other, then the derivates of the other times the oneso you correctly found the derivative of 2-3x to be -3 and based on your previous solution you also found the derivative of e^x to be e^x thus by inputting these we find

Miracrown (miracrown):

The 2 solutions won't equal each other unfortunately

Miracrown (miracrown):

this is the solution that you can simplify: \[-3e^x \space + \space (2-3x)e^x\]

OpenStudy (anonymous):

the second derivative?

OpenStudy (anonymous):

what would be the 2nd derivative?

Miracrown (miracrown):

take the derivative of the derivative; that is the second derivative

OpenStudy (anonymous):

you mean.. Im sorry Imma little bit confused

Miracrown (miracrown):

So the derivative of x^2 is 2x and the derivative of 2x is 2, thus the second derivative of x^2 is 2x

Miracrown (miracrown):

sorry, the second derivative of x^2 is 2

OpenStudy (anonymous):

second der would be (2-3x)e^x?

Miracrown (miracrown):

Ye

OpenStudy (anonymous):

Oh.. the third der would be -3e^x bla bla. Thank you =))

Miracrown (miracrown):

(:

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