gdg
Is it -3(2-3x)e^x?
Very close, this is product rule
\[(2-3x)e^x\] \[(2-3x)^\prime e^x \space + (2-3x) \space (e^x)^\prime\] \[-3e^x \space + \space (2-3x)e^x\]
Is my answer still acceptable? Or do i need to rearrange this?
(fg)'=f'g+fg' first the derivative one times the other, then the derivates of the other times the oneso you correctly found the derivative of 2-3x to be -3 and based on your previous solution you also found the derivative of e^x to be e^x thus by inputting these we find
The 2 solutions won't equal each other unfortunately
this is the solution that you can simplify: \[-3e^x \space + \space (2-3x)e^x\]
the second derivative?
what would be the 2nd derivative?
take the derivative of the derivative; that is the second derivative
you mean.. Im sorry Imma little bit confused
So the derivative of x^2 is 2x and the derivative of 2x is 2, thus the second derivative of x^2 is 2x
sorry, the second derivative of x^2 is 2
second der would be (2-3x)e^x?
Ye
Oh.. the third der would be -3e^x bla bla. Thank you =))
(:
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