What is the length of side x in the triangle below?

Question

anonymous · Answer

attachment

anonymous · Answer

@misty1212

anonymous · Answer

@iGreen

igreen · Answer

Use tangent.

$\sf tangent = \dfrac{Opposite}{Adjacent}$

$\sf tan(60^o) = \dfrac{7}{x}$

Find tan 60 degrees:

$\sf 1.73205081 = \dfrac{7}{x}$

Multiply 'x' to both sides:

$\sf 1.73205081x = 7$

Divide 1.73205081 to both sides, what's 7 / 1.73205081?

anonymous · Answer

the ratios of a 30 - 60 - 90 right triangle are 
$$1:\sqrt3:2$$ for 
short side:long side: hypotenuse

anonymous · Answer

$$\tan(\theta) = \frac{Perpendicular}{Base}$$

anonymous · Answer

you are given the long side is $7$ so the short side is 
$$\frac{7}{\sqrt3}$$ if you want a decimal, use a calculator

anonymous · Answer

$\theta = 60^{\circ}$, $Perpendicular = 7$ $Base = 7$..

anonymous · Answer

*Base = $x$..

anonymous · Answer

i would use this http://www.wolframalpha.com/input/?i=7%2Fsqrt%283%29

anonymous · Answer

$$\tan(60) = \frac{7}{x}$$

Find $x$ now..

anonymous · Answer

to confusing.....

anonymous · Answer

im gonna go threw that again igreen

anonymous · Answer

i guess $\sqrt3=1.73205081$ in this case

anonymous · Answer

ok well i got 4.04

igreen · Answer

Just divide 7 / 1.73205081..

anonymous · Answer

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