Question

Factor completely.
−64+w2

Answer 1

@Nnesha is it (w+8) (w+8)

Answer 2

nope

Answer 3

-64 + w^2 can be written as \[w^2 - 64\]
now difference of square method

Answer 4

(w +8)(w-8)

Answer 5

yep right :- )

Answer 6

\[\huge\rm (a^2 - b^2) = (a - b ) ( a + b)\]
remmber this formula for difference of square

Answer 7

and also you can only use this method if there is negative sign like in this question - 64

Answer 8

so my answer is backwards...it needs to be (w-8) (w+8)?

Answer 9

yeb one parentheses suppose be negative and one positive because when you multiply (x-8)(x-8) you should get w^2 NEGATIVE 64