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Identify the equation and graph of the line passing through point (2, -4) and having a slope of 3/2
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3x-2y=14 3x+2y=-2 -2x+3y=-16 2x+3y=-8
So you have a point, and the slope, just graph it! find out other points and plot it :)
c?
What's the slope :)
m=3
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Yup :)
I will be right back :)
so x is a 3?
M= 3/2
In need a graph
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@iGreen
Plug them into Point-Slope form. \(y - y_1 = m(x - x_1)\) Where \(y_1\) is the y-value of the point, \(x_1\) is the x-value of the point, and \(m\) is the slope. So we have: \(y + 4 = \dfrac{3}{2}(x - 2)\) Distribute 3/2 into the parenthesis: \(y + 4 = \dfrac{3}{2}x - 3\) Subtract 4 to both sides, what's -3 - 4?
I think its 3x-2y=14
-7
Yup, you're correct.
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3x - 2y = 14 is correct.
cool
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