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Mathematics 18 Online
OpenStudy (qqstory):

Calculate the first four terms of the sequence An = n + (n+1) + (n+2) + ... + (6n) , starting with n=1.

OpenStudy (anonymous):

The answer I believe is 12.

OpenStudy (qqstory):

thats not the correct answer, nice try though.

OpenStudy (qqstory):

The answer is 21 , 77 ,168,294. But how?

OpenStudy (qqstory):

I dont think i understand the question at all.

OpenStudy (anonymous):

Got a different sequence for it

OpenStudy (qqstory):

is that a question?

OpenStudy (anonymous):

Try an = 7/2(5n^2+n)

OpenStudy (qqstory):

What do you mean?

OpenStudy (qqstory):

I just dont understand the question

OpenStudy (qqstory):

And how to approach it

OpenStudy (qqstory):

iambatman are you here?

OpenStudy (qqstory):

You start with what the sequence is, like 1 and add up to 6 times of the sequence

OpenStudy (qqstory):

so 1+2+3+4+5+6

OpenStudy (qqstory):

then 2+3+4+5+6+7+8+9+10+11+12

OpenStudy (qqstory):

and the third sequence is 3+4+5+6+7+8+9+10+11+12

OpenStudy (qqstory):

pretty dumb question

OpenStudy (qqstory):

But is that the correct way to do it?

OpenStudy (anonymous):

Hey sorry, I got lost connection, and yes, that's one way, very tedious though, but remember for the third term, it's all the way up to 18

OpenStudy (qqstory):

yeah

OpenStudy (anonymous):

That's why I put the sequence above

OpenStudy (qqstory):

so what would be the correct way??

OpenStudy (qqstory):

oh

OpenStudy (anonymous):

Try plugging in your numbers

OpenStudy (anonymous):

and see if that works

OpenStudy (qqstory):

how am i supposed to figure that out on the test?

OpenStudy (anonymous):

Mhm haha, well that takes practice...I guess you might just have to do it the tedious way :\

OpenStudy (anonymous):

And see if you can find your own patterns

OpenStudy (qqstory):

i am learning about series right now in calc 2

OpenStudy (anonymous):

OOOOH

OpenStudy (qqstory):

i dont think this is even the meat of the problem

OpenStudy (anonymous):

Ok, so this is calc 2?

OpenStudy (qqstory):

yah

OpenStudy (anonymous):

Ah ok, don't worry about it too much, you will learn many methods, to deal with such things

OpenStudy (qqstory):

Can i ask you another question?

OpenStudy (anonymous):

This is just kind of testing you and seeing if you can figure it out, your way works

OpenStudy (qqstory):

\[\lim_{n \rightarrow \infty } a _{n}^{3}\]

OpenStudy (qqstory):

what does that even mean?

OpenStudy (anonymous):

an represents the nth term

OpenStudy (qqstory):

oh its just a_n^3

OpenStudy (anonymous):

so if you have a thats the first term, a2 is the second term...etc

OpenStudy (qqstory):

i got it , thanks :D

OpenStudy (anonymous):

a1*

OpenStudy (anonymous):

Cool :)

OpenStudy (anonymous):

If you have the calc textbook, I suggest you read up on sequences, it will help you wayyyy more

OpenStudy (anonymous):

Because sequences aren't really intuitive, well for me at least and the way I was taught

OpenStudy (qqstory):

thanks for the advice, will do.

OpenStudy (anonymous):

Just wondering, what textbook are you using? Stewart 7e?

OpenStudy (qqstory):

I am using this thing called launchpad

OpenStudy (qqstory):

and the book is called Calc Early Transcendentals second edition by Jon Rogawski

OpenStudy (anonymous):

Ah ok, well this site is amazing for anything calc based http://tutorial.math.lamar.edu/Classes/CalcII/Sequences.aspx check it out, it will help you tons

OpenStudy (qqstory):

Thanks

OpenStudy (anonymous):

Np :), good luck friend!

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