Mathematics
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OpenStudy (qqstory):
Calculate the first four terms of the sequence An = n + (n+1) + (n+2) + ... + (6n) , starting with n=1.
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OpenStudy (anonymous):
The answer I believe is 12.
OpenStudy (qqstory):
thats not the correct answer, nice try though.
OpenStudy (qqstory):
The answer is 21 , 77 ,168,294. But how?
OpenStudy (qqstory):
I dont think i understand the question at all.
OpenStudy (anonymous):
Got a different sequence for it
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OpenStudy (qqstory):
is that a question?
OpenStudy (anonymous):
Try an = 7/2(5n^2+n)
OpenStudy (qqstory):
What do you mean?
OpenStudy (qqstory):
I just dont understand the question
OpenStudy (qqstory):
And how to approach it
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OpenStudy (qqstory):
iambatman are you here?
OpenStudy (qqstory):
You start with what the sequence is, like 1 and add up to 6 times of the sequence
OpenStudy (qqstory):
so 1+2+3+4+5+6
OpenStudy (qqstory):
then 2+3+4+5+6+7+8+9+10+11+12
OpenStudy (qqstory):
and the third sequence is 3+4+5+6+7+8+9+10+11+12
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OpenStudy (qqstory):
pretty dumb question
OpenStudy (qqstory):
But is that the correct way to do it?
OpenStudy (anonymous):
Hey sorry, I got lost connection, and yes, that's one way, very tedious though, but remember for the third term, it's all the way up to 18
OpenStudy (qqstory):
yeah
OpenStudy (anonymous):
That's why I put the sequence above
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OpenStudy (qqstory):
so what would be the correct way??
OpenStudy (qqstory):
oh
OpenStudy (anonymous):
Try plugging in your numbers
OpenStudy (anonymous):
and see if that works
OpenStudy (qqstory):
how am i supposed to figure that out on the test?
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OpenStudy (anonymous):
Mhm haha, well that takes practice...I guess you might just have to do it the tedious way :\
OpenStudy (anonymous):
And see if you can find your own patterns
OpenStudy (qqstory):
i am learning about series right now in calc 2
OpenStudy (anonymous):
OOOOH
OpenStudy (qqstory):
i dont think this is even the meat of the problem
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OpenStudy (anonymous):
Ok, so this is calc 2?
OpenStudy (qqstory):
yah
OpenStudy (anonymous):
Ah ok, don't worry about it too much, you will learn many methods, to deal with such things
OpenStudy (qqstory):
Can i ask you another question?
OpenStudy (anonymous):
This is just kind of testing you and seeing if you can figure it out, your way works
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OpenStudy (qqstory):
\[\lim_{n \rightarrow \infty } a _{n}^{3}\]
OpenStudy (qqstory):
what does that even mean?
OpenStudy (anonymous):
an represents the nth term
OpenStudy (qqstory):
oh its just a_n^3
OpenStudy (anonymous):
so if you have a thats the first term, a2 is the second term...etc
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OpenStudy (qqstory):
i got it , thanks :D
OpenStudy (anonymous):
a1*
OpenStudy (anonymous):
Cool :)
OpenStudy (anonymous):
If you have the calc textbook, I suggest you read up on sequences, it will help you wayyyy more
OpenStudy (anonymous):
Because sequences aren't really intuitive, well for me at least and the way I was taught
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OpenStudy (qqstory):
thanks for the advice, will do.
OpenStudy (anonymous):
Just wondering, what textbook are you using? Stewart 7e?
OpenStudy (qqstory):
I am using this thing called launchpad
OpenStudy (qqstory):
and the book is called Calc Early Transcendentals second edition by Jon Rogawski
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OpenStudy (qqstory):
Thanks
OpenStudy (anonymous):
Np :), good luck friend!