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Mathematics 19 Online
OpenStudy (anonymous):

Another question.

OpenStudy (anonymous):

A rope is 50 meters long and (the rope) has the mass of 15kg. It hangs from one end off the tall building (the building is more than 50 meters). How much work is required to pull the rope up to the top of the building? (Use \(9.80~m/s^2\) for acceleration due to gravity.)

OpenStudy (anonymous):

what steps do I have to perform ?

OpenStudy (anonymous):

ALRIGHTIE A PHYSICS PROBLEM :)

OpenStudy (anonymous):

F = ma

OpenStudy (anonymous):

F= 9.8 m/s^2 times 15kg ?

OpenStudy (anonymous):

The force of a body in motion is equal to its mass times its acceleration. In terms of this specific problem, Force is equal to a body's mass times its tangential acceleration (gravitation acceleration)

OpenStudy (anonymous):

So lets see... F = (9.8 m/s^2)*(15kg) = 147 Newtons.

OpenStudy (anonymous):

how do you know 147 Newtons ?

OpenStudy (anonymous):

Work is W= F*d

OpenStudy (anonymous):

So you need to find force to calculate work.

OpenStudy (anonymous):

yes, 147, my bad.. you multiplied, I thought it would be a decimal, but it is not

OpenStudy (anonymous):

If you want to be technical, it could be .147kN. :P

OpenStudy (anonymous):

Anywho.

OpenStudy (anonymous):

k, What do I do after I found the force ?

OpenStudy (anonymous):

Since the Force is negative in this case (we are pulling it up) it is -147Newtons.

OpenStudy (anonymous):

W = -147 Newtons * 50Meters.

OpenStudy (anonymous):

pulling up is negative force ?

OpenStudy (anonymous):

Yes, because we are pulling against gravity.

OpenStudy (anonymous):

Also, wouldn't the rope be changing every bit you pull it, which would give like integral\[\int\limits_{0}^{50}...\]??

OpenStudy (anonymous):

I mean changing in weight

OpenStudy (anonymous):

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