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Find three consecutive even integers so that the sum of the three numbers is 4 more than twice the third.
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I'll give you a hint. If n is an even integer then n+2 is the next even integer. So n+(n+2) is the sum of two consecutive even integers as an example.
so 3n +2 is the sum of three consecutive even integers?
Nope, almost. For instance, 4,6, and 8 are consecutive even numbers right? So we can say n=4, n+2=6 and n+4=8 if that helps.
oh ok thanks :)
Just figure out the expression for the three consecutive even integers and you are good to go.
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