Divide.
(2x^2+21x+53)÷(x+7)
Your answer should give the quotient and the remainder.

Question

Divide. 
(2x^2+21x+53)÷(x+7)
  Your answer should give the quotient and the remainder.

anonymous · Answer

@sleepyhead314

sleepyhead314 · Answer

I'm really sorry but I personally don't know how to do this type :/

let me try to tag some other people and see if they can help ^_^

@phi @campbell_st @freckles

perl · Answer

$$\Large x+7\overline{)2x^2+21x+53}$$

anonymous · Answer

Raebeach, Patrickjmt has a really lovely video for this you can use: https://www.youtube.com/watch?v=l6_ghhd7kwQ I hope its not against the rules to post youtube links

anonymous · Answer

how do solve it @perl

campbell_st · Answer

ok... just looking at the problem the quotient is linear and the remainder is a constant

|dw:1425770584148:dw|

the process is like long division.... I multiplied the divisor (x + 7) by 2x... that way the term 2x^2 will be eliminated when the subtraction has been done. 

So can you continue the process in the division 

by 1st doing the subtraction?