What is the sum of the geometric series ? I attached an image. Its in sigma notation
I think you need to use "geometric series partial sum formula"
look it up in your notes and see if you can find it..
okay!
An=A1+(n-1) -2
nope
ohh wait thats for arithmetic right?
exactly thats for airthmetic sequence but we want "geometric series partial sum" formula
sn= a1*(1-r^n)/(1-r)
Yes thats the one
\[S_n = a_1 \dfrac{1-r^n}{1-r}\] find out the values and plug in
im not sure what i would plug in for r
we can eyeball by comparing with : \[\sum\limits_{n=0}^M a(r)^n\] we get \(r = 3/4\)
and you get first term by plugging in n=0 : \[3\left(\dfrac{3}{4}\right)^0 = 3(1) = 3\] so \(a =3 \)
since there are 19 terms, we have \(n=19\)
then the partial sum would be \[\large 3\dfrac{1- \left(\frac{3}{4}\right)^{19}}{1-\frac{3}{4}}\] simplify
11.94 ?
Thank you so much this makes so much more sense now !
umm there is an error in the solution, the values of n finish at 18... and not 19 as shown in the formula
thanks but to find n( the numbers in the solution) , you subtract the limits & add one
so n= 19
@campbell_st
Yep! im getting 11.949 which rounds to 11.9\(\color{Red}{5}\)
awesome ! thanks again!
yw!
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