2n3 = 200n
does the 3 have a sign?
\[\huge\rm 2n^3 = 200n\] like this right ??
if yes then subtract 200n both side and let me know what you get
Oh sorry, yes.
I got \[2n^3-200n=0\]
yes right now find GCF(greatest common factor)
Then I divided 2 by both sides and I got \[n^3-100n=0\]
I factored out an "n" and I got \[n(n^2-50)=0\] and because \[(n^2-50) \] my final answer was n(n+25)(n-25)=0. So I set them all to zero and I got: n=0 n+25=0 => n=-25 n-25=0 => n=25
how did you get 50?
But for some reason the website where I do my homework tells me its wrong
because I divided \[2n^3-200n\] by 2
oky right so -200 divide by 2 is what
\(\color{blue}{\text{Originally Posted by}}\) @Crazy.c.246 Then I divided 2 by both sides and I got \[n^3-100n=0\] \(\color{blue}{\text{End of Quote}}\) that's what you got after dividing by 2
yes
yes so then tha is not 50 first you have to subtract then you get |dw:1425792541421:dw|
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