Question

Find the solution of log x + log (x+1) = log 12.

Answer 1

Hint: \(\log(mn) = \log(m)+\log(n)\)

Answer 2

use the product rule for logs
\[\log a+\log b= \log\ ab\]

Answer 3

Yeah, I already got log(x^2+x) = log 12, but what would I do after that?

Answer 4

well, you basically can cancel log out. \(x^2+x\) must be equal to 12. Make sense?

Answer 5

So I can "legally" cancel out logs with the same bases all of the time?

Answer 6

Yeah

Answer 7

Great, thanks!