Question

AWARD WILL BE GIVEN AND WILL FAN
!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!METAL!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
a ball is thrown into the air with an initial upward velocity of 60 ft/s. its height (h) in feet after t seconds is given by the function h=-16t^2+60t+6. what will the height be at t=3 seconds?

Answer 1

@AlexandervonHumboldt2

Answer 2

To find the heigh of the ball at t=3 seconds, we sumply plug 3 into our h(t)= -16t^2+60t+6

h(3)= -16*(3^2)+60*3+6
h(3)= -16*9+180+6
h(3)= 42

At t=3 seconds, the ball is 42 feet above the ground.

Answer 3

@skittles_for_life6422

Answer 4

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I ALREADY FANNED YOU

Answer 5

@AlexandervonHumboldt2

Answer 6

thx a lot

Answer 7

np