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OpenStudy (anonymous):
Which figures can be used to find the area of the composite figure?
Choose exactly two answers that are correct.
http://static.k12.com/calms_media/media/1571000_1571500/1571275/1/e519ed5deb61e1623a2ad3ca3191866ec7b0899e/MS_IMB-1401208-1110601.jpg
A. a semicircle with an area of 4.5pi m2
B. a semicircle with an area of 18pi m2
C. a rectangle with an area of 33 m2
D. a rectangle with an area of 66 m2
CHOOSE ONLY 2, I THINK B AND C< I WILL GIVE MEDAL WHOM EVER HELPS FIRST
11 years ago
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OpenStudy (anonymous):
@mathmath333
11 years ago
OpenStudy (anonymous):
@kels200105 @I"like"bribro @pizza12 @KJ4UTS @Squirrels @pooja195 @xo.minnie.xox @Zyi6 @SithsAndGiggles @bibby @Mehek14 @Mesopretty @EclipsedStar @EwikaEnding @edwards555 @robtobey @rayman5766
11 years ago
OpenStudy (anonymous):
plz help i think b and c
11 years ago
OpenStudy (anonymous):
only choose 2
11 years ago
OpenStudy (mathmath333):
|dw:1425930969145:dw|
first find the area of rectangle
11 years ago
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OpenStudy (anonymous):
11 times 2 is 22
11 years ago
OpenStudy (anonymous):
and 6 times 2 is 12
11 years ago
OpenStudy (anonymous):
so 22 times 12 is...
11 years ago
OpenStudy (anonymous):
264
11 years ago
OpenStudy (mathmath333):
its not \(11\times 2=22\)
\(\text{area of rectangle}=\text{length}\times \text{breadth}\)
11 years ago
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OpenStudy (anonymous):
@bookworm14
11 years ago
OpenStudy (mathmath333):
|dw:1425931139961:dw|
11 years ago
OpenStudy (anonymous):
u mean width
11 years ago
OpenStudy (anonymous):
???
11 years ago
OpenStudy (anonymous):
oh, my bad, haha, 66 then
11 years ago
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OpenStudy (mathmath333):
yea width
11 years ago
OpenStudy (anonymous):
oh so not c, d
11 years ago
OpenStudy (anonymous):
ok, what about b though
11 years ago
OpenStudy (anonymous):
i am 99.99% sure that b is right
11 years ago
OpenStudy (mathmath333):
now find the area of semi circle|dw:1425931268401:dw|
11 years ago
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