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Mathematics 12 Online
OpenStudy (anonymous):

If the rate of change of a population is given by dP/dt= 3.1(P-2)(P-10), P>0, for what values of P is the population increasing?

OpenStudy (anonymous):

it is decreasing over the intervals where the derivative is negative

OpenStudy (anonymous):

Can you walk me through?

OpenStudy (misty1212):

HI!!

OpenStudy (misty1212):

do you know how to solve \[(p-2)(p-10)<0\]?

OpenStudy (misty1212):

not too hard since it is already in factored form it is equal to zero at \(p=2\) and at \(p=10\) since this is a parabola that opens up, it is negative between the zeros and positive outside of them

OpenStudy (anonymous):

yes

OpenStudy (anonymous):

so what do you do next ?

OpenStudy (anonymous):

you are done, there is nothing left to do it is negative on the interval \((2,1)\) and positive elsewhere

OpenStudy (anonymous):

oops i meant negative on the interval \((2,10)\)

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