746 x 7 i -4sqrt2
@SolomonZelman .
Do you know where to start @KierseyClemons on your problem?
no @Ilovecake
Help anyone?
Standard form will be something like a+bi
Been a whole since I converted them... as long as you used the proper formula based on the Euler relationship it should come out right.
The radius times the cosine is the real part and the radius times the sone is the imaginary part.
So at 5pi/6 we have \(\left(-\dfrac{\sqrt{3}}{2},\dfrac{1}{2} \right)\) Multiply the 4 through that and you get: \(\left(-\dfrac{4\sqrt{3}}{2},\dfrac{4}{2} \right)=\left(-2\sqrt{3},2 \right)\), so you will use those for your cos and sin.
Do you see how I am getting that?
I think so
Which that tells me 4squart(3) + 4i is not quite right. You are at double the values because of the canceling the half as shown in what I did.
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