Write an expression using subtraction to find the distance between skydivers A and B. Show your work and solve for the distance using additive inverses
Would this be y=-2.5 t+ x= .5?
Distance would be -2
distance can't be negative (you can't walk -2 miles)
you have 2 distances here one distance is from -2.5 to 0 -- that can be written as |-2.5 + 0| and the other distance is from 0 to 0.5 -- that can be written as |0.5 + 0|
you are using an absolute value...
I can show why this is so, on a different example: Imagine you are to find a distance from \(\large\color{black}{ \displaystyle-4}\) to \(\large\color{black}{ \displaystyle 7 }\) . and you do this on such a numberline|dw:1426112707336:dw|
|dw:1426112804495:dw|
the distance between these two points is: \(\large\color{black}{ \displaystyle \sqrt{(-4-7)^2+(0-0)^2} }\)
that simplifies to \(\large\color{black}{ \displaystyle \sqrt{(-4-7)^2} }\)
Thanks . I have to draw a number line to complete the question?
and that is just \(\large\color{black}{ \displaystyle|-4-7| }\)
or, just |-13| which is finally, 13.
using the fact that absolute value of A i.e. |A| is defined as \(\large\color{black}{ \displaystyle \sqrt{(A)^2} }\)
rate this from 0 (not at all) to 10 (perfect) .
yes, you can draw a numberline, or you can just do it off your head...
From A to B Distance: |A-B|
(assuming we are on same horizontal line)
additive inverse would to 2.5-.5?
that expression would be giving you distance from 0 to 2, OR 0.5 to 2.5 OR -0.5 to -2.5
|dw:1426113189898:dw|
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