Question

surface area integration

Answer 1

y=3x^1/3

Answer 2

rotate about the x axis

Answer 3

\[A=\int\limits_{0}^{1}2 \pi y ds\]

Answer 4

\[ds=\sqrt{1+(x^{-2/3})^{2}}dx\]

Answer 5

\[A=\int\limits_{0}^{1}\sqrt[3]{x}\sqrt{1+\frac{ 1 }{ x^{4/9} }}\]

Answer 6

I am stuck at this point and I am not sure what to use

Answer 7

you did't say what the boundaries are.... but if you are confident that surface area you are looking for is from y=0 to y=1, then ok...

Answer 8

sorry yes the boundaries are from 0 to 1

Answer 9

from y=0 to y=1, are you sure?
maybe it is from x=0 to x=1 ?

Answer 10

@recon14193 it might make things easier if you look at the integral in terms of y instead of x

Answer 11

you mean in terms of x, than y ?

Answer 12

yes it is from x=0 to x=1

Answer 13

very nice.

Answer 14

what does that mean @SolomonZelman

Answer 15

i mean putting everything in terms of y