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Mathematics 13 Online
OpenStudy (anonymous):

PLZ HELP, WILL FAN AND MEDAL!!!!! 4x^2(x)+(x)(x)^2

OpenStudy (anonymous):

\[4x^2(x)+(x)+(x)^2\] does this look correct?

DivineSolar (divinesolar):

First we will simplify.

DivineSolar (divinesolar):

When you simplify you get 4x^3 + x^3. Now we combine like term's which gives you what?

DivineSolar (divinesolar):

?

OpenStudy (anonymous):

waite, how u get 4x^3+x^3?????

OpenStudy (anonymous):

@DivineSolar

DivineSolar (divinesolar):

Well your problem is written as 4x^2 + (x) + (x)(x)^2

DivineSolar (divinesolar):

Unless it is supposed to be, 4x^2 + (x) + (x) + (x)^2

OpenStudy (anonymous):

no, is the other way but im having trouble understanding the simplofing part

DivineSolar (divinesolar):

Wait i meant 4x^2(x) + (x)(x)^2 is that correct to start out with?

OpenStudy (anonymous):

yeah thats fine

DivineSolar (divinesolar):

Ok so basically, we have -> 4x^2(x), Let us just look at that what happens when you combine x from 4x^2 x with (x)?

OpenStudy (anonymous):

umm.. u get x^2...??

DivineSolar (divinesolar):

See it is already x^2 so it would become x^3

OpenStudy (anonymous):

ok, so ur combing the x behind the 2 to the 4x^2........

DivineSolar (divinesolar):

You are combining the 4x^2's x with (x) which creates x^3, So you get 4x^3

OpenStudy (anonymous):

okay...so then u would have left 4x^3+(x)(x)^2

DivineSolar (divinesolar):

Yes you would have 4x^3+(x)(x)^2 left, So now let us look at (x)(x)^2, what do you get when you combine the 2?

OpenStudy (anonymous):

2x^2.......??

DivineSolar (divinesolar):

No. Where did you get the 2 from? There is no number behind the variable unless there already was one behind it.

DivineSolar (divinesolar):

Let's try that again, what do you get when you combine (x)(x)^2?

DivineSolar (divinesolar):

?

OpenStudy (anonymous):

lol, ok.....yeah i got nothing.....i mean the two x are multiplying each other, right?

DivineSolar (divinesolar):

No you are combining not multiplying.

DivineSolar (divinesolar):

x combined with an x would = x^2, but in this case we already have x^2 and we are combining it with (x)

OpenStudy (anonymous):

so, x^3

DivineSolar (divinesolar):

Yes there you go.

DivineSolar (divinesolar):

So now we have 4x^3 + x^3

DivineSolar (divinesolar):

Combine like terms and what do you get?

OpenStudy (anonymous):

so 5x^3 bc the like terms are x^3

DivineSolar (divinesolar):

Yes there you go!

OpenStudy (anonymous):

OMG!!!!!! THANK YOU A MILLION!!!!!

DivineSolar (divinesolar):

Sure thing.

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