Write the explicit formula that represents the geometric sequence -2, 8, -32, 128 Show work
first of what is the common ratio?
by what number do you multiply to obtain the next term? (this number is called a 'common ratio' and denoted with r)
the first term, denoted as \(a_1\) and in this case, as you can see, it is -2.
So, all you need to do, is to fill the form below, for the first term and common ratio \[\large a_n=a_{{\tiny~}_1} \left({\rm r} \right)^{n-1}\]
I am so confused
@Nnesha can you help please
okay first you need to find ( ratio) geometric sequence mean when you get next term by dividing or multiplying previous term by something so first term is -2 what you multiply with -2 to get next term which is 8 ?
i have no actual clue on how to do these. soooooo im guessing the next step would be like 8x4????
sorry to bother u but i have alot of questions i need help on today and your like the only person i know on here that actually helps me figure stuff out..
-2 times what = 8 8 times what = -32
-4?
-2x-2=8 8x-4=32 -32x4=128 ???
i think i missed a - sign or two
yep right -4 \[\huge\rm 2 \times -4 =8\] \[\huge\rm 8 \times -4 =-32\] \[\huge\rm -32 \times -4 = 128\]
now plug r value into the formula that @((*-*)) gave you
r value?
\[\huge\rm a_n = a_1 \times r^{n-1}\] r = ration a_1 = is first term
r = ratio
now i feel dumb because i have no idea what a ratio is
ratio:t he common ratio is the ratio of a term to the previous term http://www.regentsprep.org/regents/math/algtrig/atp2/geoseq.htm
does that mean the ratio is -2 and the common ratio is -4?
an= -2 x (-4) ^(n-1) is this correct?
yep right
no commone ratio is r and -2 is first term
can you show me exactly how to write this on my home work and show all my work correctly
there is not a lot work to who i already showed that how to find common ratio then you just have to use formula to plug in a_1 and r values
show*
so i show my work like -2x-2=8 8x-4=-32 -32x-4=128 an=-2x(-4)^(n-1) or do i just write an=-2x(-4)^(n-1)
yep right looks good
thanks. is it okay to tag you in a few other questions later on? it should be just check my work questions.
sure :-)
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