Question

http://prntscr.com/6g19db

Answer 1

am I right? if I am wrong why?

Answer 2

i'd like to know so I can practise on this more

Answer 3

just plugging the values you have in the table into those equations
for x=1
f(1)=4 g(1)=-1
f(1)+g(1)=3

Answer 4

and go on

Answer 5

seems that b and c are off the road
since f(x) is and exponential function
and g(x) is constant

Answer 6

ok so

A. 4^1 - 1*1 = 3

B. -1(4^1) = -4

C. 4^(1-1) = 1

D. 4^1 - 1 = 3

Answer 7

so i would say you choice is incorrect since g(x) is constant
observe that g(x)=-1 for any x
so choosing something else in not good

Answer 8

yeah... the only way offhand to do it, is to test the coordinates

Answer 9

so we have A and D.

imma try 2 now and if it equals 15 that's the answer?

A. 4^2 - 1*2 = 15

D. 4^2 - 1 = 15

but how do I know which one?

Answer 10

wait

Answer 11

first one is 14 not 15 typo

Answer 12

so it's D?

Answer 13

after doing the coordinates you need to match with what the table tells us
because we have the value of f(x)+g(x)

Answer 14

ah ok so it is D

Answer 15

i knew it had to be A or D

Answer 16

i believe that A mismatches the criteria we are looking for
it got the exponential part but the linear part is off
g(x) has to be constant -1 for any x

Answer 17

understandable

Answer 18

analytically D seems good
without going with the coordinates
other choices are off the hood
B is does not have what we look for
and c is just and exponential function

Answer 19

so according to this f(x)=4^x and g(x)=-1

Answer 20

4^x + -1 = 4^x - 1

Answer 21

if we add then we get h(x)=4^x-1
plugging some values
1 h(1)=3 check with the table
2 h(2)=16-1=15
3 h(3)=64-1 =63

Answer 22

and so on

Answer 23

yes~ of course

Answer 24

:) thanks!

Answer 25

no problem