Question

how would I solve this equation for x?

0=3.9657(0.9982^x)ln0.9982

Answer 1

\[0=3.9657(0.9982^x)\ln0.9982\]

Answer 2

first look up ln 0.9982 on your calculator and multiply what you get by 3.9657

Answer 3

For ln 0.9982, I got -0.0018 and when I multiplied it by 3.9657 I got -0.007145. Would it then be:
0=(0.9982^x)

Answer 4

$$
0=3.9657\left (0.9982^x\right )\ln {0.9982}\\
{0\over 3.9657 \times \ln {0.9982}}={\cancel{3.9657}\left (0.9982^x\right )\cancel{\ln {0.9982}}\over \cancel{3.9657} \times \cancel{\ln {0.9982}}}=0.9982^x\\
\sqrt[x]{0}=\sqrt[x]{0.9982^x}=0.9982\\
0\ne0.9982
$$
Hence, there are no solutions since 0 can not equal 0.9982.