Question

Hi! Can someone help me out with this question?
What is the extra force that ''works'' on the pool's wall that its
width is A meters, and height H meters? Thank you all!

Answer 1

@IrishBoy123 do you remember physics by any chance?

Answer 2

\[AP=F\]

Answer 3

i do not understand the question, is it written down somewhere that you could share?

Answer 4

Attached herewith the solutions for that, it's about fluids

Answer 5

I didn't understand from the third line

Answer 6

this is the force due to pressure in a fluid - Bernoulli's equation for pressure: P + rho•g•h + 1/2 rho• v^s = constant. the force does no work in a swimming pool in the sense that it does not cause something to move. the Force is calculated as A • pressure. it just tries to push the wall......

what i mean is that IF you are trying to answer a question in a text book or exam, copy it on here and let's see what this is all about.

Answer 7

I cannot see what you wrote...

Answer 8

ah!! i get it. integrating rho•g• h with respect to h gives the h^2 / 2 term. the integration calculated the force over an are rather than the force at a point.

the bar on P indicates you are calcing average foece or pressure.

Answer 9

refresh screen.

Answer 10

because the pressure increases linearly with depth, you find the average using integration and apply that to a wall will give you the total force on that wall.

i can try draw something later, if you need it.

Answer 11

wow you're brilliant! how did you infer it all?

Answer 12

so, when it comes to pools/pressure gets higher the more you go deeper, I need to use the average

Answer 13

but, the initial pressure is zero?

Answer 14

rho*g*h?

Answer 15

Can you please clarify this to me?

Answer 16

@IrishBoy123 ?

Answer 17

It would be much appreciated if you could draw it later, I'm afraid I didn't understand everything...

Answer 18

@IrishBoy123 a miracle just happened, I've got it!!!!! Thanks a lot!

Answer 19

cool!!!