Question

Find the point(s) on the graph of y=e^(-x^2) at which the curvature is zero.

Answer 1

@hartnn @Compassionate @ParthKohli @.Sam.

Answer 2

I may not have a solution for you, but may I ask what math class this is from?

Answer 3

also is it (-x)^2 or -(x^2)

Answer 4

It's Calculus 3. \[y=e ^{-x^2}\]

Answer 5

@zepdrix @thomaster

Answer 6

why not find the 1st derivative... and then find the stationary points.

Answer 7

curvature is not the same as gradient. it measures the change of direction (a vector) wrt to arc length.

parameterising is easier, i think, which gives me this:



that means curvature = 0 @ x = 1.

the workings could be wrong - have done this quite quickly - but the idea behind it is right.