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Mathematics 9 Online
OpenStudy (anonymous):

@jtvatsim

OpenStudy (anonymous):

OpenStudy (anonymous):

Im just unsure how it did the transformation from the integral to the sequence because the t^2n-1 turned into t^2n and then a random 2n came into the denominator

OpenStudy (jtvatsim):

They are following the integral rule that int(x^n) = x^(n+1) / (n+1). In this case the power was p = 2n-1, so when integrated p = 2n, but then we need t^2n / 2n. That is where the factor came from.

OpenStudy (anonymous):

Oh thats just basic integral stuff. Idk why i didnt see that

OpenStudy (anonymous):

alright thank you haha. I should be finished with this stuff soon

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