Question

how is x/ (x^2-1) simplified to 1/(x-1) ?

Answer 1

nope that's not right

Answer 2

again \[\huge\rm a^2 - b^2 = (a+b)(a-b)\]
difference of square method
x^2-1 can't be x(x-1)

Answer 3

what about x^3-9/ (x+3) ?

Answer 4

x^3 or x^2 ?

Answer 5

cubed

Answer 6

okay for difference of square method there should be negative sing and both term suppose to be perfect square root

Answer 7

sign** :D

Answer 8

for that one you have to divide x^3 -9 by x+3

Answer 9

and how do I do that ?

Answer 10

two ways
1) long division
2)synthetic division
which one is easy for you ?

Answer 11

I have no idea

Answer 12

what's synthetic division ?

Answer 13

hmmm so haven't ' learned this yet? right :(
what's your question divide or simplify for 2nd one

Answer 14

I want to simplify

Answer 15

\[\huge\rm \frac{ x^3 -9 }{ x+3 }\]its already simplified

Answer 16

hm wait is this ur question \[\huge\rm \frac{ x^3 }{ x+3 } -9\] ??

Answer 17

no it's the first one

Answer 18

difference of cubes ?know anything about this method ?

Answer 19

a3 + b3 = (a + b)(a2 – ab + b2)

Answer 20

but cubert 9 is a decimal

Answer 21

yeah

Answer 22

bec 9 is not a perfect cube root

Answer 23

yeah thanks anyway

Answer 24

np :)