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Determine the minimum value of the function f(x)=4^x -8. I found the derivative f'(x)-4^x ln4. Would I do f'(x)=0 and solve for x?
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\[4^{x} -8\]
yes, f'(x) = 0 gives you extreme points
Ok I did that and got 0=4^x ln4 and that would turn to 0=4^x. would would i isolate x?
can 4^x ever be = 0 ?
for any value of x ?
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nope
then this function does have any minimum :)
Oh ok! thanks!
or you can say, it has a minimum at \(\Large -\infty \) which is same as saying it does not have a minimum \(4^{-\infty } = 0 \)
and welcome ^_^
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